Explanation

$logx + 2 = 1 + logy$

$logx + 2 - logy = 1$

$log_{10}^{\frac{x + 2}{y}}$ $= 1$

$\frac{x+2}{y} = 10^1$

$x + 2 = 10y$

$y = \frac{x+2}{10}$

$logx + 2 = 1 + logy$

$logx + 2 - logy = 1$

$log_{10}^{\frac{x + 2}{y}}$ $= 1$

$\frac{x+2}{y} = 10^1$

$x + 2 = 10y$

$y = \frac{x+2}{10}$