Explanation

Convert to base 10

given: $1P122_3 = 98_{10}$

→ $1^4P^31^22^12^0 = 98_10$

$1 × 3^4 + P × 3^3 + 1 x 3^2 + 2 x 3^1 + 2 = 98$

$81 + 27P + 9 + 6 + 2 = 98$

$98 + 27P = 98$

$27P = 0$

$P = \frac{0}{27} = 0$

Convert to base 10

given: $1P122_3 = 98_{10}$

→ $1^4P^31^22^12^0 = 98_10$

$1 × 3^4 + P × 3^3 + 1 x 3^2 + 2 x 3^1 + 2 = 98$

$81 + 27P + 9 + 6 + 2 = 98$

$98 + 27P = 98$

$27P = 0$

$P = \frac{0}{27} = 0$