passpadi

2022

Chemistry

POST UTME

A gas with an initial volume of 6.5 dm2^2 is heated and allowed to expand to 19.5m2^2 at constant pressure. What is the ratio of the initial absolute temperature to the final absolute temperature?


A.

2:5

B.

4:5

C.

3:8

D.

1:3


Correct Answer:

1:3


Explanation

V1_1= 6.5 dm3^3 , V2_2 = 19.5dm3^3

V1T2\frac {V_1}{T_2} =V2T2\frac {V_2}{T_2}, T1T2\frac {T_1} {T_2} = V1V2\frac {V_1}{V_2}

=6.5dm319.5dm3\frac {6.5dm^3}{19.5dm^3}

=1:3

V1_1= 6.5 dm3^3 , V2_2 = 19.5dm3^3

V1T2\frac {V_1}{T_2} =V2T2\frac {V_2}{T_2}, T1T2\frac {T_1} {T_2} = V1V2\frac {V_1}{V_2}

=6.5dm319.5dm3\frac {6.5dm^3}{19.5dm^3}

=1:3

passpadi
©2023 Passpadi. All rights reserved.